Comments on: Last-day-of-month cron job

By: waldner

waldner — Fri, 29 Jun 2012 13:07:32 +0000

In reply to kanchan. In which way it does not work? Does the script run at all? You should be able to get some info from the cron log (don't know where it is on CentOS, may be /var/log/cron.log or /var/log/daemon.log or yet something else). Also make sure your cron support the 28-31 syntax (it should).

By: kanchan

kanchan — Fri, 29 Jun 2012 12:43:58 +0000

Below is not working for me on linux centos machine. Added below line /etc/crontab 0 23 28-31 * * root [ "$(/bin/date +\%d -d tomorrow)" = "01" ] && php /var/www/html/test/myfile.php Please help

By: waldner

waldner — Wed, 21 Mar 2012 16:45:53 +0000

In reply to Chad. You are right, percent signs need to be escaped in crontab files (I was even bitten recently by this). Thanks, I've updated the text.

By: Chad

Chad — Wed, 21 Mar 2012 16:41:16 +0000

In the GNU cron tab entry, I had to escape the % on a RHEL system. 0 23 28-31 * * [ "$(/bin/date +\%d -d tomorrow)" = "01" ] && /your/script.sh

By: Carl Wenninger

Carl Wenninger — Thu, 18 Aug 2011 21:58:37 +0000

An excellent discussion of this topic!

Here is a C-Variant of the above Perl-Code.
The cmd-part of the crontab-line will look like
is-last-day-month && my-cron-job.sh

#include

int main()
{
time_t t;

t = time(NULL) + 86400;
return localtime(&t)->tm_mday == 1;
}